A. 6.0 x 104JC-1
B. 4.0 x 104JC-1
C. 1.2 x 104JC-1
D. 8.0 x 104JC-1
Correct Answer:
Option A – 6.0 x 104JC-1
Explanation
2000W heater → 2000J/S
=> Heat supplied by the heater within 10 min
(600 seconds) = 2000 x 600
= 1200000J
∴ Heat capacity MC = 1200000/(30-10)
= 60000J/C
Heat capacity = 6.0 x 104JC-1
![A solid of mass 0.5kg initially at 50oC melts at 60oC. Calculate the quantity of heat required to melt it completely. [specific heat capacity of the solid =2.0KJ kg-1K-1][Specific latent heat of fusion of solid =1.0 KJ kg-1] A solid of mass 0.5kg initially at 50oC melts at 60oC. Calculate the quantity of heat required to melt it completely. [specific heat capacity of the solid =2.0KJ kg-1K-1][Specific latent heat of fusion of solid =1.0 KJ kg-1]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png)
