A. 3.8H
B. 0.6H
C. 0.4H
D. 0.2H
Correct Answer: Option B
B. 0.6H
Explanation
XL = V/I=240/2=120Ω
L = XL/2Ï€f
= 120×π/2×π×100
= 0.6H
![A coil of inductance 0.12 H and resistance 4Ω, is connected across a 240V, 50Hz supply. Calculate the current through it. [π = 3.142]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "A coil of inductance 0.12 H and resistance 4Ω, is connected across a 240V, 50Hz supply. Calculate the current through it. [π = 3.142]")
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