A spiral spring of natural length 30.0cm and force constant of 20Nm‾¹ is compressed to 20.0cm. Calculate the energy stored in the spring

By: |Published on: May 22|Categories: Physics WAEC| 0 comments

A. 0.1J
B. 1.0J
C. 10.0J
D. 100.0J

Correct Answer: Option A

Explanation

Energy = ½ke²=½ × 20×0.1²

= 0.1J

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