Consider the following equation; Cr2O7²-(aq) + 14H+(aq) + 6e- → 2Cr3+(aq) + 7H2O(I). The oxidation number of chromium changes from?

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A. -2 to + 3
B. – 2 to + 6
C. + 6 to + 3
D. + 7 to + 6

Correct Answer: Option C

C. + 6 to + 3

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