A. 0.60A
B. 0.97A
C. 1.03A
D. 5.00A

Correct Answer: Option B

B. 0.97A

Explanation

1/R=1/R1+1/R2

= 1/6+1/4

R = 12/5=2.5Ω

R = 2.4 + 10 = 12.4

V = IR

SEE ALSO  A loaded spring performs simple harmonic motion with an amplitude of 5cm. If the maximum acceleration of the load is 20cms‾¹, calculate the angular frequency of the motion

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