A converging lens of focal length 10cm forms an erect image three times the size of the real object. Calculate the distance between the image and the object.

By: |Published on: Jan 24|Categories: Physics WAEC| 0 comments

A. 6.6cm
B. 11.1cm
C. 13.3cm
D. 20.0cm

Correct Answer: Option C

Explanation

Given, image size = 3U

object size = U

focal length = 10cm

lens to object distance = (focal length×object size) / imagesize
= 10×u/3u = 3.33
distance between image and object = 10 + 3.33 = 13.33cm

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