A. 30°
B. 45°
C. 60°
D. 90°

Correct Answer: Option B

B. 45°

Explanation

The formula is v²sin²θ/g

And the sine graph is highest at 1 with its inverse as 90°. Hence, 2θ = 90°

θ = 45°

SEE ALSO  Simple harmonic oscillator has a period of 0.02s and amplitude of 0.25m. Calculate the speed in ms-1 at the centre of the oscillation.

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