Find the equation of a line perpendicular to the line 4y = 7x + 3 which passes through (-3, 1)

By: |Published on: Jan 7|Categories: Mathematics WAEC| 0 comments

A. 7y + 4x + 5 = 0
B. 7y – 4x – 5 = 0
C. 3y – 5x + 2 = 0
D. 3y + 5x – 2 = 0

Correct Answer: Option B

B. 7y – 4x – 5 = 0

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