The empirical formula of a compound containing 0.067mol Cu and 0.066mol O is [Cu = 63.5, O = 16]

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A. Cu2O
B. CuO
C. CuO2
D. CuO4

Correct Answer: Option B

Explanation

Cu : O

0.067 : 0.066

mole ratio 0.067/0.066 : 0.066/0.066

= 1 : 1

= CuO

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