A. 3.7dm³
B. 11.2dm³
C. 22.4dm³
D. 33dm³
Correct Answer:
Option B – 11.2dm³
Explanation
Molar mass of methane = 16g/mol
At S.T.P. its 8g occupies 11.2
so 16g occupies 22.4 dm³
Molar mass of propane = 44g/mol¹ occupies 22.4dm³ at S.T.P
so 22g will occupy 11.2dm³
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![Calculate the mass of chlorine gas which occupies a volume of 1.12 dm³ a volume of 1.12 dm³ at s.t.p [Cl = 35.5, 1 mole of gas occupies 22.4 dm³ at s. t. p ]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "Calculate the mass of chlorine gas which occupies a volume of 1.12 dm³ a volume of 1.12 dm³ at s.t.p [Cl = 35.5, 1 mole of gas occupies 22.4 dm³ at s. t. p ]")