A. Carbon (II) oxide
B. Carbon (IV) oxide
C. Oxygen
D. Nitrogen
Correct Answer:
Option C – Oxygen
Explanation
2CO + O2 → 2CO2
50cm³ → 25cm³
20% X 150 = 30cm³
30cm³ is the volume of oxygen available for the reactions. But only 25 cm³ is required; therefore O2 is in excess