A. 85cm3
B. 50cm3
C. 125cm3
D. 55cm3
Correct Answer:
Option B – 50cm3
Explanation
Since 2 mol H2 reacted with 1 mol of O2
: 50cm3 of hydrogen reacted with 25cm3 of oxygen
Remainder oxygen = Supplied amount – Reacted amount → 75cm3 – 25cm3 = 50cm3
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![Calculate the mass of chlorine gas which occupies a volume of 1.12 dm³ a volume of 1.12 dm³ at s.t.p [Cl = 35.5, 1 mole of gas occupies 22.4 dm³ at s. t. p ]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "Calculate the mass of chlorine gas which occupies a volume of 1.12 dm³ a volume of 1.12 dm³ at s.t.p [Cl = 35.5, 1 mole of gas occupies 22.4 dm³ at s. t. p ]")
