A. 0.5 mol dm³
B. 0.6 mol dm³
C. 0.2 mol dm³
D. 0.4 mol dm³
Correct Answer:
Option A – 0.5 mol dm³
25cm³ of a 0.2 mol dm³ solution of Na2CO3 requires 20 cm³ of a solution of HCl for neutralization. The concentration of the HCl solution is?
![Calculate the mass of chlorine gas which occupies a volume of 1.12 dm³ a volume of 1.12 dm³ at s.t.p [Cl = 35.5, 1 mole of gas occupies 22.4 dm³ at s. t. p ]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "Calculate the mass of chlorine gas which occupies a volume of 1.12 dm³ a volume of 1.12 dm³ at s.t.p [Cl = 35.5, 1 mole of gas occupies 22.4 dm³ at s. t. p ]")
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