Zn(s) + 2HCI(aq) → ZnCI2(aq) + H2(g) [Zn = 65; 1 mole of a gas occupies 22.4dm³ at s.t.p]
A. 0.040dm³
B. 0.896dm³
C. 5.82dm³
D. 8.62dm³
Correct Answer:
Option B – 0.896dm³
Explanation
Zn(s) + 2HCI(aq) → ZnCI2(aq) + H2(g)
65g of Zn produces 22.4 dm³ of H2; .: 2.6g of Zn will produce = 2.6/65 x 22.4 = 0.896 dm³
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