What volume of hydrogen is produced at s.t.p. When 2.60 g of zinc reacts with excess HCI according to the following equation?

Zn(s) + 2HCI(aq) → ZnCI2(aq) + H2(g) [Zn = 65; 1 mole of a gas occupies 22.4dm³ at s.t.p]

A. 0.040dm³
B. 0.896dm³
C. 5.82dm³
D. 8.62dm³

Correct Answer:

Option B – 0.896dm³

Explanation

Zn(s) + 2HCI(aq) → ZnCI2(aq) + H2(g)

65g of Zn produces 22.4 dm³ of H2; .: 2.6g of Zn will produce = 2.6/65 x 22.4 = 0.896 dm³