What quantity of heat is required to convert 20 g of ice at 0 ºC to water at the same temperature? (Specific latent heat of ice = 336 Jg−1)

A. 7.06 x 10³J
B. 5.38 x 10³J
C. 6.72 x 10³J
D. 1.35 x 10³J

Correct Answer:

Option C = 6.72 x 10³J

Explanation

quantity of heat = mass * Specific latent heat → 20 * 336

quantity of heat = 6720j or 6.72 x 103J