A. 135.0cm³
B. 150.0cm³
C. 45.0cm³
D. 90.0cm³
Correct Answer:
Option D – 90.0cm³
Explanation
CH4(g) + 2O2(g) → 2H2O(g)
1 volume of methane will react with 90cm³of oxygen at S.T.P
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