Cu2S(g) + O2(g) → 2Cu + SO2(g)
A. 0 to + 2
B. 0 to + 1
C. + 1 to 0
D. + 2 to + 1
Correct Answer:
Option C = + 1 to 0
Explanation
In the reactant;
Cu2S
2Cu – 2(1) = 0
2Cu = 2
Cu = 2/2
Cu = +1
In the product, Cu
Cu = O
The oxidation number of Cu in Cu2S and Cu respectively is +1 and 0 respectively
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