What amount of mercury would be liberated if the same quantity of electricity that liberates 0.65g of zinc is applied?

A. 2.01g
B. 1.00g
C. 4.02g
D. 8.04g

Correct Answer:

Option C = 4.02g

Explanation

Zn²⁺ + 2e^– → Zn

2F will be liberated 65g of Zn, if 0.65gm of Zn is liberated, the quantity of electricity used
X = (0.65/65) X 2
= 0.02F

∴ Hg⁺ + e^– → Hg¹
i.e 1F → 201gm of Hg

∴ 0.02 will liberated
Y = (0.02/1) X 201
= 4.02g