A. 500.0J
B. 250.0J
C. 62.5J
D. 50.0J
E. no correct option
Correct Answer:
Option E = no correct option
Explanation
Total inductance,L = L¹ + L² = m
15 + 5 = 20mH = (20)H/1000
1 = 5A
Energy of inductor, ½LI²
= (1)/2 X (20)/1000 X 5‾²
= 0.25 J
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