Physics JAMB

Two inductors of inductance 4 II and 8 II are arrange in series and a current of 10 A is passed through them. What is the energy stored in them?

A. 600 J
B. 50 J
C. 133 J
D. 250 J

Correct Answer:

Option A – 600 J

Explanation

Inductance (L) in series: 4 + 8 = 12

Therefore Energy stored =

W = ½LI²
= ½ ×12×10²
= 600J

Sunday

Share
Published by
Sunday
Tags: physics

Recent Posts

List of Universities Offering Veterinary Medicine in Nigeria

Veterinary medicine is the branch of medicine that deals with the prevention, diagnosis, and treatment…

2 months ago

List of Universities Offering Anthropology in Nigeria

Anthropology is the scientific study of human beings and their cultures. It encompasses a wide…

2 months ago

List of Universities Offering Sociology in Nigeria

Sociology is the scientific study of human society, culture, and behavior. It examines the social…

2 months ago

List of Universities Offering Social Work in Nigeria

Social Work is a profession dedicated to helping individuals, families, and communities to cope with…

2 months ago

List of Universities Offering Religious Studies in Nigeria

Religious studies is an academic discipline that explores the beliefs, practices, and history of various…

2 months ago

List of Universities Offering Public Administration in Nigeria

Public administration is the field of study and practice that focuses on the organization and…

2 months ago