Categories: Physics WAEC

Two bodies of masses 3.0 kg and 2.0 kg are separated by a distance of 50 cm. Calculate the force of attraction between them. [G = 6.67 x 10¯¹¹ Nm² kg² ]

A. 1.6 x 10−9N
B. 1.3 x 103N
C. 2.3 x 103N
D. 5.0x 103N

Correct Answer:

Option A = 1.6 x 10−9N

Explanation

Using the formula

F = Gm1m2/r2
= 6.67×10−11×3.0×2.0/(50)2
= 40.02×10−11/2500
= 1.6 x 10−9N

Sunday

Share
Published by
Sunday

Recent Posts

ENG 201 Theory Questions: Phonetic Symbols

200 Level Spoken English Practice exam questions and detailed answers. Download the answers in document format.…

18 hours ago

ENG 201 Theory Question: Intonation Functions And Importance

200 Level Spoken English Practice exam questions and detailed answers. Download the answers in document format.…

18 hours ago

EME 201 Theory Question: Phases In English Plosives

200 Level Spoken English Practice exam questions and detailed answers. Download the answers in document format.…

19 hours ago

ENG 201 Theory Questions: Speech Organs

200 Level Spoken English Practice exam questions and detailed answers. Download the answers in document format.…

19 hours ago

EME 411 Theory Question: School Budget Planning

400 Level Basic Concept In Educational Planning And Administration Practice exam questions and detailed answers. Download…

20 hours ago

EME 411 Theory Question: Social Demand Approach

400 Level Basic Concept In Educational Planning And Administration Practice exam questions and detailed answers. Download…

20 hours ago