Two balls X and Y weighing 5g and 50kg respectively were throne up vertically at the same time with a velocity of 100m/s¹. How will their positions be one second later?

A. X and Y will be 500 m from each other
B. Y will be 500 m ahead of X
C. X will be 500 m ahead of Y
D. X and Y both be 500 m from the point of throw

Correct Answer:

Option D – X and Y both be 500 m from the point of throw

Explanation

v² = U² – 2gs
0 = 100² – 2 x 10 x s = 10000 – 20s
s = (10000)/20 = 500m

Which is independent of mass. The two bodies were acted upon by the same retarding force of gravity which is independent of mass of the body; therefore both will be 500 m from the point of throw.