Three capacitors of capacitance 2μF; 4μFand 8μF are connected in parallel and a P.D of 6V is maintained across each capacitor. The total energy stored is?

A. 2.52 x 10^-6J
B. 6.90 x 10^-6J
C. 2.52 x 10^-4J
D. 6.90 x 10^-4J

Correct Answer:

Option C – 2.52 x 10^-4J

Explanation

C = C1 + C2 + C3
= 2 + 4 + 8 = 14μF
V = 6V

Energy = ½CV²
½ x 14 x 10^-6 x 6²
= 2.52 x 10^-4J