The pressure of one mole of an ideal gas of volume10‾²m³  at a temperature of 27°C is [molar gas constant = 8.3 J mol‾¹k‾¹]

A. 2.49 x 10⁴ Nm^-2
B. 2.24 x 10⁴ Nm^-2
C. 2.49 x 10⁵ Nm^-1
D. 2.24 x 10⁵ Nm^-1

Correct Answer:

Option C = 2.49 x 10⁵ Nm^-1

Explanation

T = 27 + 273 = 300K, volume, V = 10^-2 m³  molar gass constant, R = 8.3 J mol‾¹k‾¹ number of mole, n = 1
PV = nRT
i.e P = (nRT)/V = (1 x 8.3 x 300)/10^-2
= 2.49 x 10⁵ Nm‾¹