![The percentage composition of a hydrocarbon is 79.2 carbon 20.8 hydrogen. Calculate its empirical formula [H = 1, C = 12]](https://erudites.ng/wp-content/plugins/accelerated-mobile-pages/images/SD-default-image.png)
![The percentage composition of a hydrocarbon is 79.2 carbon 20.8 hydrogen. Calculate its empirical formula [H = 1, C = 12]](https://erudites.ng/wp-content/uploads/2020/06/past-questions-and-answers.jpg)
A. CH
B. CH3
C. CH4
D. C2H2
E. C2H6
Correct Answer:
Option B – CH3
Explanation
Relative No of Moles for Carbon = 79.2% ÷ 12 = 6.6
Relative No of Moles for Hydrogen = 20.8% ÷ 1 = 20.8
Ratio of Moles = Carbon 6.6 ÷ 6.6 = 1 Hydrogen = 20.8 ÷ 6.6 = 3
CH3
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