The number of sulphur atoms in 3.20g of SO2(g) is [O = 16.0;S = 32.0; Avogadro constant = 6.02 X 10²³]

A. 3.01 x 10²²
B. 6.02 x 10²²
C. 6.02 x10²³
D. 1.20 x 10²¹

Correct Answer: Option B

B. 6.02 x 10²²

Explanation

32g of sulphur = 6.02 x 1022 atoms 3.2g of sulphur = x ,x = \(\frac{3.2×6.02 x 1023}{32}\) = 0.602 x 1023 = 6.02 x 1022 atom