The mass of silver deposited when a current of 10A is passed through a solution of silver salt for 4830s is? (Ag = 108; F= 96500 mol-¹)

A. 54.0g
B. 27.0g
C. 13.5g
D. 108.0g

Correct Answer:

Option A – 54.0g

Explanation

Recall that

mass deposited = MmIt/96500n

Mm =108, t = 4830s

I = 10A, n = 1

m = 108 × 10 × (4830/96500) × 1

m = 54.0g