The mass of one mole of (NH4)2CO3 is [O=16.0, N=14.0, C=12.0, H=1.0]

A. 66.0g
B. 76.0g
C. 80.0g
D. 96.0g

Correct Answer: Option D

D. 96.0g

Explanation

This is same as asking for the molar mass of the compound

= (2×14.0)+(8×1.0)+12.0+(16.0×3)
= 28.0+8.0+12.0+48.0 = 96.0g