The lowest note emitted by a stretched string has a frequency of 40Hz. How many overtones are there between 40Hz and 180Hz?

A. 4
B. 3
C. 2
D. 1

Correct Answer:

Option B – 3

Explanation

The lowest note (fundamental note) emitted by any stretched string has a fundamental frequecy fo = V/2l = 40Hz
The 1st overtone = 2fo = 2 x 40 = 80Hz
2nd overtone = 3fo = 3 x 40 = 120Hz
3rd overtone = 4fo = 4 x 40 = 160Hz
4th overtone = 5fo = 5 x 40 = 200Hz

Overtones between 40Hz and 180Hz are 80Hz, 120Hz, 160Hz = 3 Overtones