A. 5 x 104 J
B. 4 x 102 J
C. 4 x 10-3 J
D. 5 x 10-4 J
Correct Answer:
Option D = 5 x 10-4 J
Explanation
The energy stored in a given capacitor is given by
E = 1/2 CV2 = 1/2 QV = 1/2Q2/C
Where C = the capacitance of the capacitor
Q = charge carried by the capacitor
V = p.d across the plates of the capacitor thus from the data given, C = 10μF
= 10 x 10-6F
Q = 100μc = 100 x 10-6C
∴ Energy stored = 1/2 Q2/C
| = | 1 |
| |||
| 2 |
| = | 1 |
| |||
| 2 |
5.0 x 10-4
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