The electric field intensity in a place where a charge of 10^-10C experiences a force of 0.4N is?

A. 4.0 x 10⁷ NC^-1
B. 8.0 x 10⁹ NC^-1
C. 8.O x 10^-12 NC^-1
D. 4.0 x 10⁹ NC^-1

Correct Answer:

Option D – 4.0 x 10⁹ NC^-1

Explanation

The electric force experienced in an electric field of intensity E is given by:
F = qE: where q = the test charge.
E = F/Q = 0.4/10^-10 = 0.4 X 10^-10
= 4.0 X 10⁹ NC^-1