One mole of a compound M(HCO3)2 has a mass of 162g. Calculate the relative atomic mass of M. [H = 1, C =12, O = 16]

A. 122
B. 101
C. 53
D. 40

Correct Answer:

Option D – 40

Explanation

One of the mole of M(HCO3)2 = 162g; M +(1 + 12 + 16 x 3) x 2 = 162; M +122 = 162,:. M = 162 – 122 = 40g