A. 1.7V
B. 2.0V
C. 8.0V
D. 15.0V
Correct Answer:
Option B – 2.0V
Explanation
For a photoemitted electron,
eV = K.E.max, where V = stopping potential and K.E. = maximum kinetic energy of the photo emitted electron given by K.E. = Energy of incident rad – Work – function
= 5ev – 3ev = 2ev
∴ eV = 2eV
V = 2eV/e = 2V
∴ Stopping Potential = 2.0V
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