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WEEK 3
TOPIC: AREA OF SHAPES
CONTENTS:
AREA OF CIRCLES
Where π = 22/7
Diameter = 2r, where r = radius
Example:
Solution:
Area of a circle = πr2
= 22/7 × (3½)2 = 22/7 × 7/2 × 7/2
=
= 77/2 m2 = 38.5m2
Solution
Area of circle = πr2
253/2 = 22/7 r2
253 X 7 = 22 X 2 X r2
r2 = 161/4
r = √161/4
r = 12.689/2
r = 6.345
r = 6.35 (2 d. p.)
AREA OF TRIANGLES
Any diagonal of a rectangle divided it into two equal right- angled triangles forms a right angled triangle.
Thus:
Area of a right – angled triangle
= ½ × product of sides containing the right angle.
Area of triangle = ½ × base × height.
Example:
Calculate the area of the triangle shown below;
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