In the diagram given, the current passing through the 6Ω resistor is 1.5A. Calculate the terminal p.d. of the battery in the diagram

A. 7.50V
B. 9.00V
C. 10.80V
D. 1.25V

Correct Answer: Option C

C. 10.80V

Explanation

C.V = 1R1 + 1R2

= (1.2 x 1.5) + (1.5 x 6)

= 1.8 + 9

= 10.80V