Physics JAMB

In a hydraulic press; a force of 40N is applied on the effort piston of area 0.4m². If the force exerted on the load piston is 400N; the area of the large piston is?

A. 4m²
B. 8m²
C. 2m²
D. 1m²

Correct Answer: Option A

Explanation

Pressure developed in the effort piston = F/a
F/a = 40/0.4 = 400/4 = 100Nm2
this pressure is transmitted to the larger piston of area A; => P = F/A
∴ 100 = 400/A
=> A = 400/100 = 4m2

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