In a hydraulic press; a force of 40N is applied on the effort piston of area 0.4m². If the force exerted on the load piston is 400N; the area of the large piston is?

A. 4m²
B. 8m²
C. 2m²
D. 1m²

Correct Answer: Option A

Explanation

Pressure developed in the effort piston = ^F/_a
∴^F/_a = ⁴⁰/_0.4 = ⁴⁰⁰/₄ = 100Nm²
this pressure is transmitted to the larger piston of area A; => P = ^F/_A
∴ 100 = ⁴⁰⁰/_A
=> A = ⁴⁰⁰/₁₀₀ = 4m²