If two charged plates are maintained at a potential difference of 3 kv; the work done in taking a charge of 600 µC across the field is?

A. 0.8 J
B. 1.8 J
C. 9.0 J
D. 18.0 J

Correct Answer:

Option B = 0.8 J

Explanation

Work done = product of the charge Q, and the p.d V.
(i)/e work done = Q.V = 600 x 10^-6 x 3.0 x 10^-3 = 1.8 J.