If the quantity of oxygen occupying 2.76L container at a pressure of 0.825 atm and 300k is reduced by one-half; what is the pressure exerted by the remaining gas?

A. 1.650atm
B. 0.825atm
C. 0.413atm
D. 0.275atm

Correct Answer:

Option A = 1.650atm

Explanation

Using the combined gas law formula,

Given that P₁ = 0.825, V₁ = 2.76 L, V₂ = 1.38 L, P₂ = ?

And T₁ = T₂; we would have P₂ = [ P₁ X V₁ ] ÷ V₂
: [0.825 X 2.76] ÷ 1.38

= 1.650atm