A. +2081 Jmol‾¹
B. -2081 Jmol‾¹
C. -649 Jmol‾¹
D. +649 Jmol‾¹
Correct Answer:
Option A = +2081 Jmol‾¹
Explanation
∆G = ∆H – T∆S
-899 = ∆H – 2980
∆H = -899 + 2980 = + 2081 Jmol-1
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