Given that 32.0g sulphur contains 6.02 x 10²³ sulphur atoms how many atoms are there in 2.70g of aluminium? {Al = 27, S =32}

A. 6.02 x 10²³
B. 3.01 x 10²²
C. 6.02 x 10²²
D. 5. 08 x 10²²
E. 3.01 x 10²²

Correct Answer:

Option C – 6.02 x 10²²

Explanation

1g Al = 6.02×10²³ /27

2.7g Al = (6.02×10²³ / 27)×2.7

= 6.02×10²²Al atoms