Physics JAMB

Calculate the upthrust on an object of volume 50cm³ which is immersed in a liquid of density 103kgm−³ [g = 10ms−²]

A. 0.8N
B. 2.5N
C. 0.5N
D. 1.0N

Correct Answer:

Option C – 0.5N

Explanation

Upthrust = change in weight

density = mass/volume

Mass of liquid displaced = Density of Liquid × Volume;

= 10³×50×10^−6m³

= 0.05kg

(Note that the volume of 50cm³ was converted to m³ by multiplying by 10^6) i.e 50cm³=50×10^−6m³

Since mass displaced = 0.05kg

Upthrust = mg = 0.05 × 10

= 0.5N

Sunday

Share
Published by
Sunday
Tags: physics

Recent Posts

OOU JUPEB Admission For Agricultural Extension

Do you want to study Agricultural Extension in OOU? Before you apply for the OOU…

10 months ago

OOU JUPEB Admission For Agricultural Economics

Do you want to study Agricultural Economics in OOU? Before you apply for the OOU…

10 months ago

OOU JUPEB Admission For Cooperative and Business Management

Do you want to study Cooperative and Business Management in OOU? Before you apply for…

10 months ago

OOU JUPEB Admission For Home and Hotel Management

Do you want to study Home and Hotel Management in OOU? Before you apply for…

10 months ago

OOU JUPEB Admission For Animal Production

Do you want to study Animal Production in OOU? Before you apply for the OOU…

10 months ago

OOU JUPEB Admission For Crop Production

Do you want to study Crop Production in OOU? Before you apply for the OOU…

10 months ago