Calculate the specific latent heat of vaporization of steam of 1.13 x 106J of heat energy is required to convert 15kg of steam to water.

A. 7.53 x 105 Jkg−¹

B. 7.53 x 10-2 Jkg−¹

C. 7.53×104 Jkg−¹

D. 7.53 x 10-3 Jkg−¹

Correct Answer:

Option C – 7.53×104 Jkg−¹

Explanation

Quantity of heat = mass(m) × specific latent heat (L)
Q = m/L
L = Q/m

= 1.13×10^6/15

= 7.53×10^4Jkg−¹