An organic compound contains 72% carbon; 12% hydrogen and 16% oxygen by mass. What is the empirical formula of the compound? [ H = 1.0. C = 12.0, O = 16.0 ]

A. C₃H₈O
B. C₆H₁₂O
C. C₆H₁₂O₂
D. C₁₂H₁₂O₁₁

Correct Answer:

Option B – C₆H₁₂O

Explanation

C = 72 / 12 H = 12 / 1 O = 16 / 16

C = 6 H = 12 O = 1

: EMPIRICAL FORMULA

C₆H₁₂O