An object is protected with a velocity of 100m‾¹ at an angle of 60° to the vertical. Calculate the time taken by the object to reach the highest point (Take g as 10ms‾²)

A. 5.0s
B. 8.7s
C. 10.0s
D. 17.3s
E. 20.0s

Correct Answer:

Option B – 8.7s

Explanation

t = T/2=1/2

=2usinθ/g=(100×sin60)/10

10 sin60 = 10 x 0.8660

= 8.7

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