An electron of charge 1.6 x 10^-19C is accelerated between two metal plates. If the kinetic energy of the electron is 4.8 x 10^-17J, the potential difference between the plate is?

A. 30V
B. 40V
C. 300V
D. 400V

Correct Answer:

Option C – 300V

Explanation

In general, if a charged particle is accelerated between two metal plates/a region by potential difference V volts, the work done on the charge, given by the product of the charge and the potential difference, is equal to the kinetic energy of the charge
Thus eV = K.E
1.6 x 10^-19 x V = 4.8 x 10^-17

= 300V