A solid weighs 4.8g in air; 2.8g in water and 3.2g in Kerosene. The ratio of density of the solid to that of the kerosene is

A. 2
B. ³/₂
C. ²/₃
D. 3

Correct Answer:

Option D = 3

Explanation

Relative density of solid= ^{weight of solid}/_{weight of an equal volume of water}

= ^4.8/_4.8−2.8

= ^4.8/₂ = 2.4

Relative density of liquid = ^{Weight of liquid kerosene}/_{Weight of an equal volume of water}

= ^4.8−3.2/_4.8−2.8 = ^1.6/₂ = 0.8

= ^{Ratio of relative density of solid}/_{Relative density of Kerosene}

= ^{density of solid}/_{density of Kerosene}

= ^2.4/_0.8

= 3