A resistance thermometer has a resistance of 20Ω at 0°C and 85Ω at 100°C. If its resistance is 52Ω in a medium, calculate the corresponding temperature

A. 49.2°C
B. 60.6°C
C. 80.0°C
D. 84.7°C

Correct Answer: Option A

A. 49.2°C

Explanation

85Ω ……..100°C

52Ω ……..θ°C

20Ω ……..0°C

(52−20)/(85−20) = (θ−0)/(100−0)

θ = (32×100)/65

=49.2°C