Physics WAEC

A ray of light is incident at an angle of 30°on a glass prism of refractive index 1.5. Calculate the angle through which the ray is minimally deviated in the prism. (The medium surrounding the prism is air)

A. 10.5°
B. 19.5°
C. 21.1°
D. 38.9°
E. 40.5°

Correct Answer:

Option A – 10.5°

Explanation

n = sin i/sin r

sin r = 30°/n

sin r = 0.51.5

sin r = 0.3333

r = 19.5°; Deviation 30 – 19.5 = 10.5°

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