A near sighted student has a near point of 0.1m and a focal length of 5.0cm. What is the student’s far point?

A. 0.200m
B. 8.000m
C. 0.125m
D. 2.100m
E. No Correct Option

Correct Answer:

Option E = No Correct Option

Explanation

The person’s image distance v will be at the distance of 0.1m = 10cm for him to see objects at a distance of u.F = 5.0cm

1/v+1/u=1/f ⟹ 1/10+1/u=1/5

1/u=1/5−1/10 = (2−1)/10

1/u = 1/10 therefore u = 10cm=0.1m