A motorcycle starting from rest is uniformly accelerated such that its velocity in 10s is 72kmhr¯¹. What is its acceleration?

A. 108ms^-2
B. 86ms^-2
C. 4ms^-2
D. 2ms^-2

Correct Answer:

Option D = 2ms^-2

Explanation

where u = o m/s, t = 10s,

v = 72kmhr−1 —> (72 X 1000) / 3600

: v = 20 m/s

Acceleration (a) = ( v – u ) / t —> (20 – 0) / 10

: a = 2m/s²